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8 Feb 2012 00:32:39 IST
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Consider a solid conducting sphere with a radius 0.7 cm and charge ?7.3 pC on it. There is a conducting spherical shell concentric to the sphere. The shell has an inner radius 2.8 cm(with 2.8 cm > 0.7 cm) and outer radius 5 cm and a net charge 27.9 pC on the shell. Denote the charge on the inner surface of the shell by Q?2 and that on the outer surface of the shell by Q??2. Find the charge Q??2. Answer in units of pC
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8 Feb 2012 15:59:38 IST
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Electrostatics
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8 Feb 2012 16:00:06 IST
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Electrostatics
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8 Feb 2012 16:47:15 IST
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35.2
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8 Feb 2012 21:30:19 IST
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But how??
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8 Feb 2012 23:07:05 IST
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Whats th Answer
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10 Feb 2012 22:11:50 IST
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? stands for what
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11 Feb 2012 11:11:23 IST
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ans is 35.2pc....the solid sphere inside the shell acts as a point charge...since the field inside the conductor should b zero,the inner surface of the shell develops a negative charge of 7.3pc...the shell already has a charge of 27.9pc,since charge should b conserved the charge that appears on the outer shell is 27.9+7.3=35.2pc
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