hey, the bulb gives 100 W at 220 Volts
hence, P = V^2 / r
P = 100 W , V = 220 V .....
r = V^2 / P
r = 220*220 / 100
r = 48400/100
or r = 484 ohms....
resistance of the bulb is 484 ohms....
when it is operated at 150 V , power = 150*150 / 484
i.e powe rwud be around 46.5 W .....