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8 Feb 2009 20:13:39 IST
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A: All physically correct equations are dimensionally correct.
R: Physical correctness depends on dimensional correctness and the numerical values of dimensionless constants used a. if both are correct and 2nd is proper xplanation of 1st. b. if both are correct and 2nd is not proper xplanation of 1st. c. if 1st is true and 2nd is false d. if both are false
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assertion is true. because, if its dimensions are not correct, then it would not be physically correct.REASON IS CORRECT EXPLAINATION OF ASSERTION.I THINK SO.
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28 Feb 2009 00:54:42 IST
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A - stat. 1 is correct and stat. 2 is correct explanation of stat. 1 same reasaon as APOORV PANSE
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tbgandhi29 |
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28 Feb 2009 01:30:49 IST
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d.
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NIT silchar electrical engineering |
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28 Feb 2009 01:39:19 IST
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i agree wid ramyani...it shud be d!
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1 Mar 2009 22:20:01 IST
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It is b).Statement two doesn't explain statement one. But both are correct. Statement two covers statement one also.Ramyani pls explain your answer
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1 Mar 2009 22:40:20 IST
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answer is c....2nd one z wrong
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1 Mar 2009 22:45:31 IST
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yes (A) same reason as apoorv..... but i have a doubt.... vel. in nth second Snth = u + a(2n-1)/2 ..... if u check dimensions then [S] = [L] while [RHS] = [LT-1] how????
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2 Mar 2009 07:38:58 IST
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2 Mar 2009 15:52:24 IST
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IN EQUATION, Snth = u + a(2n-1)/2there is a hidden dimension of " t ".actully, t is 1sec because we r calculating for " nth" second.WE USUALLY NEGLET THE DIMENTION OF TIMES = u(1sec) + a(2n-1)/2ab aaya samajh me?
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24 Mar 2009 20:58:39 IST
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its A because a dimensially incorrect equation would be definately incorrect.........
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Dont walk as if u rule the world.......
walk as if u dont care who rules the world!!!!!!!! |
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