In a reaction 10 grams of MnO2 on heating completely gets coverted to MnO3 .The weight of MnO3 produced is?

since whole of the MNO2 is finished so

according to the equivalent concept

n1 z1 = n2 z2 no of equivalents of MNO2 = no of equivalents of MNO3

 where z1 and z2 are the respective z factors or the n factors

10/molecular mass of MNO2 x 4 =w/molecular mass of MNO3 x 6

on solving we get w = 7.87 gms