A magnet of length 10 cm and magnetic moment 1 Am^2 is placed along the side AB of a equilateral triangle ABC. If the length of side AB is 10 cm, the magnetic field at point C is?
YOU can use this formula to calculate as u know area of equilateral triangle...but u also know there is no FIELD in AC and BC because of consider the direction current in a loop...from C you can draw angle bisector on AB and you get angle
ANGLE 30 degree each now you can apply biot saverts law to calculate B magnetic field at C due current wire AB.
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