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Ask community Community Discussion Question: a drunker walking in a narrow lane takes 5 steps forwrd and 3 steps backward, followed again by 5 st
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charvi saraswat (2)

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a drunker walking in a narrow lane takes 5 steps forwrd and 3 steps backward, followed again by 5 steps forward and 3 steps backward and so on. each step is 1m long and requires 1 sec. deterine hw long the drunker takes to fall in a pit 13m awy frm the start??? this is class 11 ncert ques. pg56. q3.4. pls help!!! if u have ncert then pls tell me q3.7, 3.8, 3.9.....pls plspls...
    

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winx (1236)

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5 steps forward + 3 steps backward

so ultimately 2 steps forward in total of 8 steps

i.e., 2 steps in 8 seconds(since each step in 1 sec)

i.e., 2m in 8 sec (as 1 step = 1m)

so , 8m in 32 seconds ...........................(1)

   

now only 5 m remains.......

he'l cover dat 5m in the 1st 5 steps .......i.e., 5 sec(coz he takes 5 steps ahead & den 3 steps back......so 1st 5 steps)

 

coz 1nce he fell in da pit, he can't get out of dat  2 hav 3 steps backward as per  ur question............so those 3 steps(3m,3sec) r not considered over here....

 

so,   5 m in 5 sec  (coz 5m in 5 steps each of 1m covered in 1 sec).......................(2)

 

so from (1) & (2) overall   13 m  in   32 + 5 = 37 sec

 

 

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charvi saraswat (2)

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wow!!! great....thnxx....


crazy abt SCIENCE!!!!
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