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Ask community Community Discussion Question: A man with a parachute is bailed out at a height of 400 m. I f time taken for 1st 200 m fall is
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Pratik Somani (0)

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A man with a parachute is bailed out at a height of 400 m. I f time taken for 1st 200 m fall is t1 and for 2nd 200 m fall is t2, then

1)t1<t2

2)t1>t2

3)t1=t2

4)information is not sufficient

please give a short explanation too.

    

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ankit mishra (0)

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ti>t2..... it is so because the person jumping from the plane has 0 speed and hence is falling  under gravitational force,whereas in second case he has some initial velocity after trvelling a distance 200m..... for more pls try newtons 2nd law

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hey ankit.......consider the viscous+buoyant force acting on the man.......think about it again.......please do reply
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i hope the answer will be the same as stated above cause the forces will be sme during the entire period of motion..... by the what is the answer given?
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The force wont be the same.....as the Stoke's force varies with velocity..........the ans given is t1
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SOMEBODY HELP!!!!!!!!!!!!!!1
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