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18 Feb 2010 12:33:15 IST
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a ray incident on a plane mirror. for what angle of incident the ray wll undergo deviation of 4pi/5 radian???
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crazy abt SCIENCE!!!! |
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19 Feb 2010 21:02:12 IST
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Hello charvi, You have not mention that the medium change or not, If It's travel in both Rare and denser medium we ca use n1*sin(ө1)=n2*sin(ө2) So,n1 and n2 are two mediums and ө1 is indent ray angle , the deviation 4pi/5 radians is known as 144 degrees,Hense by above n1 and n2 are same in the air i.e 1.33.sin(144)=sin(ө) ө=36 degrees
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19 Feb 2010 21:03:26 IST
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Hello charvi,I am not sure I may think................... You have not mention that the medium change or not, If It's travel in both Rare and denser medium we ca use n1*sin(ө1)=n2*sin(ө2) Here,n1 and n2 are two mediums and ө1 is indent ray angle , the deviation 4pi/5 radians is known as 144 degrees,Hense by above n1 and n2 are same in the air i.e 1.33.sin(144)=sin(ө) ө2=36 degrees
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19 Feb 2010 21:09:03 IST
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ah...its obvious dude....medium doesnt change.....
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20 Feb 2010 13:50:33 IST
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ok...but the answer is 18 degree.... and medium kyu change hoga???? mirror hai na... to bas reflection hi to hoga????
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crazy abt SCIENCE!!!! |
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20 Feb 2010 14:38:30 IST
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First understand that the angle of deviation is the angle between the initial direction of incident ray and reflected raythen, draw a diagram i+r=pi-4*pi/5 then angle of incidence = (i+r)/2 =pi/10 =18 degrees
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