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8 Apr 2009 00:23:55 IST
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A GOOD QUESTION ~ HAVE A LOOK ~ FIND THE SOLUBILITY OF Mg(OH)2 (Ksp = 10-12 ) IN A SOLUTION OF pH VALUE 12 ??? A) 10-8 B)10-6 C)10-5 D)10-10
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8 Apr 2009 00:27:59 IST
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niche wali post dekho 
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don't walk as if u rule d world
walk as if u dont care who rules d world
-this is knw as attitude
B who u r and say wat u feel ......
coz those who mind don't matter ........
and those who matter dont mind ......... :)
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8 Apr 2009 00:31:02 IST
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don't walk as if u rule d world
walk as if u dont care who rules d world
-this is knw as attitude
B who u r and say wat u feel ......
coz those who mind don't matter ........
and those who matter dont mind ......... :)
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8 Apr 2009 00:31:53 IST
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is the answer 10^-10 ???
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8 Apr 2009 00:33:02 IST
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its the same method i did and same answer i got, but "luckily" no option is matching ~~~~~~ :D
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8 Apr 2009 00:34:22 IST
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the answer says 10 ^ -8 !!!!!!!! i m really shocked ~~~~ :(
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8 Apr 2009 00:39:33 IST
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haan aa toh gaya dear we get .25 *10^-8 n solubility we measure in small nos n nt 25 n so....... so tahts d answer posted d sol bove :)
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don't walk as if u rule d world
walk as if u dont care who rules d world
-this is knw as attitude
B who u r and say wat u feel ......
coz those who mind don't matter ........
and those who matter dont mind ......... :)
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ya sorry...it is 10^-8.....[Ba2+] = S' , [OH-] = S' + 10^-2 now apply Ksp = (2S' + 10-2)2 (S').......omit the S2 and S3 terms as they are very small. u will get 10^-8
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8 Apr 2009 10:17:59 IST
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Mg(OH)2 = Mg2+ + 2OH- [OH-] = 10^-2 (pOH = 2) [Mg2+] = s [Mg2+] [OH-]^2 = 10^-12 [Mg2+](10^-2)^2 = 10^-12 So s = 10^-8.
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