A piece of blue glass heated to a high temperature and a piece of red glass at room temperature, are taken inside a dimly lit room, then:

a. the blue glass will look blue and red will look red as usual

b. red look brighter and blue look ordinary blue

c.blue shines like brighter red compared to red piece

d. both pieces look equally red.

 the answer is 'blue shines brighter red as compared to the red piece'....

d reason is since blue glass was heated to a higher temperature it will glow more brightly acc to kirchoff's law: good absorbers are good emitters...

Good absorber are good emitter - Kirchoff's Law

and acc. to Prevost's Law any body at any temp more than 0K emits heat radiations

In dark/dimly lit room    Emitted heat>Absorbed heat

so if the blue piece absorbs red wavwlwngth it will emit red wavelength,

m 1/T  for cooresponding wavelength of MAXIMUM spectral emissive power for a BLACK BODY.

At certain TEMP, on increasing , spectral emissive power increases upto maximum value after which it decreases.

the temp. is not constant in your case.

hope it helps