a quantity with fixed magnitude but no fixed direction

let initial velocity be u

let final velocity be v

because K.E.remains same

mu²/2  =  4mv²/2

u  =  2v

v  =  u/2

so the velocity should be halved

(1+i)/(1-i) = (1+i)/(1-i)  *   (1+i)/(1+i)  =   (1+2i+i²)/(1-i²)   =  2i/2  =  i

[(1+i)/(1-i)]^m  =  1

i^m  =  1

least value of m = 4 because i⁴ = 1

the equilateral triangle inscribed in circle will have max. area

QR = r* sqrt(3)

area = sqrt(3) * r * sqrt(3)/4 = 3r/4

in the sol. given by Chandrashekher just put W=1 as work done is 1

so the eq would be

1/8 = 4x + 6y                  -(1)

1/10 = 3x + 7y            -(2)

solving the two u will get y =1/100

so work done by 10 women in 1 day = 10y = 1/10

no. of days required to 1 work = 10 

it will remain at the top because as the string breaks both the block & the wedge begins to fall with acceleration g & since both were initialy at rest & their relative acceleration is 0 therefore they will remain in same position with respect to each other & because the block was initially at the top of the wedge hence it will remain their in complete fall

supplement angles are those whose sum is 180

let angle be x

so its supplement = x/3

x + x/3 = 180

4x/3=180

x = 135

supplement of x = 45

nucleus is not a sphere which u will split.it is just a collection of protons & nuetrons

no because electron can be anywhere around the nucleus.Even at infinite distance from nucleus the probability of finding electron is not zero

since s & p elctrons are tightly held by nucleus lie before f-electron so, they effectively shield 5f electrons 

since 5f electrons are not tightly held by nucleus therefore they have wide empty spaces between them so they are unable to shield electrons behind it effectively & hence have poor shielding effect

sp³hybridisation as it forms 3centre-2electron bond or banana bond ie 2 electron are shared between 3 atoms

as u can see B forms 4bonds so it is sp³hybridised

2+5=7

monosubstituted benzene has no isomers

disubstituted benzene has three isomers

initial total mass of car = 20+5=25kg

massof grain leaked after 10 sec =10*0.2=2kg

final mass of car = 25-2=23kg

let final velocity be v

apply conservation of momentum

25*20 = 23*v

v =21.7m/sec

next smallest of zeros in which a factorial can not end is 11

because 5! ends in one 0

10! ends in two 0

15! endsin three 0

20!ends in four 0

but 25! ends in six 0 because 25 multiplied by a mutiple of 4 gives no. ending in two 0

similarly 30! ends in seven 0

35! ends in eight 0

40!ends in nine 0

45! ends in ten 0

but 50! will end with twelve 0 as 50 multiplied by any even no. will give a no. ending in two 0