dissociation constant is higher for ch3-br than ch3-f

Me2C=CH2 more stable than MeHC=CHMe due to greater no. of alpha hydrogen atoms per molecule.

Acetylide, ethynide, dicarbide, or percarbide is the divalent anion with formula C22− or (C≡C)2−. It may be regarded as the result of removing two protons from acetylene C2H2 or H-C≡C-H, the prototypical alkyne — that behaves as a weak acid.

ethanol has high boiling point than diethyl ether beacuse of much stronger hydrogen bonding in ethanol as compared to diethyl ether

Two -OH groups cannot be attached to one carbon simultaneously because this state is a high energy state i.e very unstable. Two +M groups can never be attached to same carbon atom in aliphatic compound because they will pull excessively the electron cloud of carbon and a high energy state will be formed. stronger +M group usually removes weaker +M group from that carbon.

Yes, Aniline & ethyl amine react with Grignard reagent to give alkanes beacuse R in grignard reagent accept's acidic hydrogen from aniline and ethylamine to give RH which is an alkane. Now depending RMgX selected alkane will differ 

eg.

CH₃CH₂NH₂ + CH₃MgBr ----> CH₃CH₂NHMgBr +CH₄

There is 1 sigma bond in a single bond.

There is 1 sigma bond and 1 pi bond in a double bond.

There is 1 sigma bond and 2 pi bond in a triple bond.

So count the no. of single double and triple bonds in the given structure and thus evaluate the no. of sigma and pi bond on the basis of fundamental explianed above

In iupac nomenclature we should keep in mind the following naming scheme-

Senior most funtional group>similiar functional group>multiple bond>max no of carbon atom>max no of substituent>lowest set of locant>alphabetical order

yes they are enentimers as they are non superimposable mirror images.

i think it should be methanal instead of methyal.

methanal - HCHO

CHCl₃ + CH₃CH₂NH₂ ------> CH₃CH₂NC.

this is known as carbylamine test.

 p-toluidene is more basic than  m-toluidene because in p-toluidene hyperconjugation effect of CH₃ is available, whereas in m-toluidene hyperconjugation effect is not present because hyperconjugation does not acts at meta position

concentrated H2SO4  is more strong.

actually there is nothing like neo propyl bromide.....it should be n-propyl bromide....

yes they are enantiomers because structure of both the compunds are non superimposble mirror images.

A bicyclic molecule is a molecule that features two fused rings. Bicyclic molecules occur widely in organic and inorganic compounds.

Fusion of the rings can occur in three ways:

·         Across a bond between two atoms - for example, decalin (also known as bicyclo[4.4.0]decane), has a C-C bond shared between two cyclohexane rings;

·         Across a sequence of atoms (bridgehead) - for example, norbornane (also known as bicyclo[2.2.1]heptane), can be viewed as a pair of cyclopentane rings that share three of the five carbon atoms; or

·         At a single atom (spirocyclic, forming a spiro compound)

Bicyclic molecules have a strict nomenclature. On its simplest level the parent hydrocarbon is the equivalent open carbon alkane. For bridged compounds, the prefix bicyclo is added, followed by, between brackets, separated by periods, and in descending order, the number of carbon atoms between each of the bridgeheads. For example in bicyclo[2.2.1]heptane the carbon frame contains a total of 7 atoms hence the parent name heptane. This molecule has three bridges having 2, 2 and 1 carbon atoms hence the prefix bicyclo[2.2.1]. For spiro compounds, terms like spiro[2.4] are used, indicating that there are 3- and 5-membered rings (because the spiro atom itself is not counted) meeting at the spiro atom.