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Heat Transfer
Tags: Engineering Entrance  |  IIT JEE  |  Thermal Physics
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Heat Transfer Numericals - IV

HARD:
H1. The rate at which the radient energy reaches the surface from the sun is about 1.4 kw/m2. The distance from the earth to the sun is about 1.5 x 1011 and the radius of sun is about 0.7 x 109m

(a) What is the rate radiation of energy, per unit area from the sun's surface?

(b) What is the temperature of sun's surface assuming it to be a black body?
Solution: (a) The energy crossing through a unit area per second

=    D: Distance between sun and earth.

= 1.4 x 103

P = 3.96 x 1026

= 6.43 x 107 wm-2
(b) = 1

E = T4

T = = 5803 K

H2: A 2m long wire of resistance 4 ohm and diameter 0.64 is coated with plastic insulation of thickness 0.06mm. when a current of 5a flows through the wire, find the temperature difference across the insulation in steady state if K = 0.16 x 10-2 cal/cm 0c see.
Solution: H =

H = -

Q1 - Q2 = 20 c

H3: Consider a spherical black body for the body to cool down from 1000k to 300 K ? Density of Cu = a x 103 kg/m3 and specific heat = 4 KJ/kg.
Solution: = AT4

= mc







   t = 127 x 103 sec


Keywords
(1) Conduction
(2) Convection
(3) Radiation
(4) Absorptive Power(a)
(5) Emmissive Power(e)
(6) Emmisitivity
(7) Black Body

 

 
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